Logic Q

[FORTUNATO]

Originally posted by amina_imen

Originally posted by FORTUNATO
My setup doens not show any grey area

2(pi)R scare?

OK then the area inside the created space inside the circle..i.e. the three shapes that look like rose petals.

One more detail, distance between A, B or C and tip of adjacent petal is equal to R!

Well;

= (2*3,14*R*R)/6

[amina_imen]

Originally posted by FORTUNATO
Well;

= (2*3,14*R*R)/6

How? what does the comma mean in your answer?
I don't think that's the answer.

[3rdTroop]

One needs to be a great INTEGRATOR.
tip: integrate once and then multiply by 6.


circle with centre (a, b) and radius r has equation:
(x minus a)2+(y minus b) 2 =R2


[Edited by 3rdTroop on 17th January 2005 at 20:37]

[3rdTroop]

Originally posted by FORTUNATO
Well;

= (2*3,14*R*R)/6
[/B]

This gives you 1/6 of the surface of the circle

[kerbacs2]

Originally posted by 3rdTroop
One needs to be a great INTEGRATOR.
tip: integrate once and then multiply by 6.


circle with centre (a, b) and radius r has equation:
( x − a )2 + ( y − b )2 = R2

[Edited by 3rdTroop on 17th January 2005 at 20:35]

dont we need for that the parametric equation for each of the six curves (which is the same) along the radius?

[amina_imen]

Originally posted by amina_imen

Originally posted by FORTUNATO
Well;

= (2*3,14*R*R)/6

How? what does the comma mean in your answer?
I don't think that's the answer.

Just got your answer meant: (2*Pi*R^2)/6 (where R^2 = R squared)

You mean 1 sixth of the area of the circle!

I don't think it's the answer but why do you think that?

[amina_imen]

Originally posted by 3rdTroop
One needs to be a great INTEGRATOR.
tip: integrate once and then multiply by 6.


circle with centre (a, b) and radius r has equation:
(x minus a)2+(y minus b) 2 =R2


[Edited by 3rdTroop on 17th January 2005 at 20:37]

So what's the answer?
(what's R2? R squared?)