Logic Q

[Bibi_Nasima]

Sounds like you guys are fab at math. I have a math test tomorrow morning and will need tutoring afterwards Can I ask for help?

[Bibi_Nasima]

Did I kill you board??

[Shotokan_Karate]

Salaam,

To cut a long story short, I would say:

Grey Area = Area of circle O - Area of the inscribed equilateral hexagon

no?

[3rdTroop]

Originally posted by amina_imen

Originally posted by 3rdTroop
One needs to be a great INTEGRATOR.
tip: integrate once and then multiply by 6.


circle with centre (a, b) and radius r has equation:
(x minus a)2+(y minus b) 2 =R2


[Edited by 3rdTroop on 17th January 2005 at 20:37]

So what's the answer?
(what's R2? R squared?)

yes R2 is R squared

a=b=1/2*R* sqroot(2) = 0.7071*R

[amina_imen]

Originally posted by Shotokan_Karate

Salaam,

To cut a long story short, I would say:

Grey Area = Area of circle O - Area of the inscribed equilateral hexagon

no?

Which is?

[amina_imen]

Originally posted by 3rdTroop
yes R2 is R squared

a=b=1/2*R* sqroot(2) = 0.7071*R

You mean the length AB = 0.7071*R

By visualising the picture again, you can see AB can't be smaller than R.

[Shotokan_Karate]

Which is:

Grey Area = (Pi R^2) - (3 sq root 3 / 2)R^2

Which means:

Grey Area = R^2 ( Pi - 3 sq root 3 / 2)