Logic Q

[amina_imen]

Originally posted by Shotokan_Karate

Which is:

Grey Area = (Pi R^2) - (3 sq root 3 / 2)R^2

Which means:

Grey Area = R^2 ( Pi - 3 sq root 3 / 2)

The unknown area is what is left around the outside of the circle, between the circumference and the outside side of each triangle. This unknown area is split into six congruent sections (equal in every way - like the triangles are "equal" in every way - including area, length of side and length of arc).

Each triangle, is equilateral. Each of the 3 sides of each triangle is a radius (R).

The area of the leftover sections outside the triangles, but inside the circle can be found by subtracting the area of the equilateral hexagon from the area of the circle, or by substracting the area of the triangles from the area of the circle (need to find an area of one of the equilateral triangles and multiply by 6).



That would be:
Pi*R^2 - [(3 sqrt 3)/2 * R^2]
= Pi - (1.5 sqrt 3 )* R^2

[Shotokan_Karate]

Thank you

[3rdTroop]

goooooooooooooood answer.
u used a shortcut

[amina_imen]

Originally posted by 3rdTroop
goooooooooooooood answer.
u used a shortcut

There must be lots of ways of solving the problem, but yours must be more complicated

[Shotokan_Karate]

Get prepared for another one

- Given five zeroes, using any mathematical operations, can you make a total of 120?

[amina_imen]

Only zeroes??

[Shotokan_Karate]

That's right dear rival