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Thread: Logic Q

  1. #925
    k_s
    k_s is offline Registered User
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    A maximal triangle would be (L/3)*H/2, H= sqrt((L/3)^2+(L/6)^2)
    A cirle would be: 3.14 * ((L/3.14)/2)^2
    A maximal square would be: (L/4)^2.

    Calculate which one is bigger.

  2. #926
    phylay is offline Guest
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    Quote Originally Posted by k_s
    A maximal triangle would be L^2/2 (equal sides) or whatver is the rule cannt remember
    A cirle would be: 3.14 * ((2*L/3.14)/2)^2
    A maximal square would be: (L/2)^2.

    Calculate which one is bigger.
    So you are not considering a crescent or a star?

  3. #927
    Damya is offline Registered User
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    Quote Originally Posted by phylay
    If you join the two ends of a thread of length L, what is the gemetric figure you must form to maximise the area?
    cercle d'air 2(L^2)/Pi,
    sinon caree yatla3 4(L^2) ce qui est moins.
    LAla?
    "Ghir ladjbel alli mayatlakawach"
    "Il n'y a que les montagnes qui ne se rencontrent jamais"

  4. #928
    k_s
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    Quote Originally Posted by phylay
    So you are not considering a crescent or a star?
    Nope they just too slim lol
    I ahve to be doing a degree in maths to know the rule for the area of a crescent, a star may be

  5. #929
    phylay is offline Guest
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    Quote Originally Posted by Damya
    cercle d'air 2(L^2)/Pi,
    sinon caree yatla3 4(L^2) ce qui est moins.
    LAla?
    Verifi hsabatek, carre machi hakdak... w balak moustatil?

  6. #930
    phylay is offline Guest
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    Quote Originally Posted by k_s
    Nope they just too slim lol
    I ahve to be doing a degree in maths to know the rule for the area of a crescent, a star may be
    Lol, u r right, too slim
    As for the crescent it is built using two circles donc area = areas diff.
    nedjma, I might calculate it by parts (triangles and the polygone) or use the surrounding circle

  7. #931
    k_s
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    Yes the problem is in finding the appropriate radius for each of the circle.

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